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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2008 22:13:37 IST
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four solid spheres(radius=r) r present at the corners of a sq. . what is the moment of inertia abt axis passing through any side note the outer spheres r just revolving not rotating (inner ones i.e on the axis must be rotating)
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18 Feb 2008 22:18:37 IST
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This is the way to do it: For the spheres on the axis, note that the axis passes through the COM, so use the well known formula for MI. For the balls on the other two edges, Find the moment of inertia about the center of mass, and then use parallel axis theorem. It is a simple exercise, and I think you'll be able to do it. Please do invest some time on thinking over it and give it an honest attempt. If you are not able to get it, I will post the complete solution.
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Will nip in at times to solve problems :)
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18 Feb 2008 22:29:58 IST
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u r ans will be 8/5mr^2+2mR^2
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18 Feb 2008 22:31:25 IST
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Is there any ambiguity in the answer? What is the side of the square by the way?
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Will nip in at times to solve problems :)
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18 Feb 2008 22:51:02 IST
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side=R
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