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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2008 14:54:39 IST
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we have 2 spheres one of which is hollow and the other is solid they have identical masses and MI about their respective diameters the ratio of their radii is given by
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20 Apr 2008 15:07:21 IST
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MI r given ??
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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20 Apr 2008 15:10:07 IST
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no they r not given
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20 Apr 2008 15:10:58 IST
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root 5/3 Identical mass and MI so 2/3 MR2 = 2/5 MR'2
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I Tried So Hard And Got So Far
But In The End
It Doesnt Even Matter... |
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20 Apr 2008 15:14:13 IST
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no the ans is not that
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20 Apr 2008 15:15:10 IST
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wts d answer den dude?
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I Tried So Hard And Got So Far
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It Doesnt Even Matter... |
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20 Apr 2008 15:18:10 IST
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hey pinnacle look masses r same not both radius and masses..
ok !! i give u the soln..
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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20 Apr 2008 15:20:06 IST
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since MI r same ( language nahi samjh paya tha)..
and so r the masses...
therefore...
2/3 r^2 = 2/5 R^2...
thus r/R = root ( 3/5)
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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20 Apr 2008 15:21:03 IST
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Brother
we have been given dat mass and MI is same
i havnt taken radii to be same too
i hav taken dem as R and R'
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I Tried So Hard And Got So Far
But In The End
It Doesnt Even Matter... |
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20 Apr 2008 15:22:19 IST
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rite ..but see yaar !!..u forgot to take the underoot..
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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20 Apr 2008 17:07:19 IST
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yes it should be root 3/5 or root 5/3. if the ans. is diff then. that ans. is wrong. or the question is wrong
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20 Apr 2008 20:44:47 IST
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let the two spheres have masses m and radii r and r' ( r----solid sphere,,.. r" --- hollow sphere)
for solid sphere
MI = 2/5 mr2
for hollow sphere
MI = 2/3mr"2
2/3mr"2 = 2/5mr
r"2/3 = r2/5
r"/r=  (3/5)
pls rate if it helped...
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