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Scorching goIITian

Joined:	2 Jan 2012
Post:	213

7 Jun 2012 21:03:39 IST

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237

momentum

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Two identical trucks each of mass M (excluding sacks of rice) move on national highways with speeds v1 and v2 towards each other. When they meet each other, a sack of rice of mass m is thrown from one truck to the other and an identical sack of rice is thrown from the second to the first. Calculate their velocities v1? and v2? after the exchange of sacks, given m = 50 kg, M = 200 kg, v1 = 50 m/s and v2= 200 m/s. Friction of the road may be neglected.

Comments (1)

Juhi Sharma

Blazing goIITian

Joined: 22 May 2009

Posts: 2467

9 Jun 2012 12:07:47 IST

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consider first truck with speed 200m/sec and 50Kg sac with speed 50m.sec

Conserve momentum as their final velocity would be same.

150*200-50*50/200=v

137.5m/sec

Now simillarly conserve for other

-150*50+200*50=200V

V=12.5m/sec

The direction of motion of both the truck would be same.

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