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Mechanics

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 Joined: 17 Aug 2007 Post: 17
8 Sep 2007 22:55:58 IST
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A stone thrown vertically upwards when particle is at a height half of its speed is 10 m/s then max height attained by particle is ....... ( S = 10 m/s2 )

(a) 8m                  (b) 10m
(c) 15 m               (d) 20m

Hot goIITian

Joined: 6 Jun 2007
Posts: 144
8 Sep 2007 23:20:04 IST
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plz make d ques clear
"at a height half of its speed is 10 m/s"
this is a confusing portion

Cool goIITian

Joined: 23 Jun 2007
Posts: 30
8 Sep 2007 23:39:39 IST
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I think the question may be typed wrong. The question may be
"A stone thrown vertically upwards when particle is at a half height of its speed is 10 m/s then max height attained by particle is ....... ( S = 10 m/s2 )"
that is the half and height are interchanged while typing by mistake

let us consider the suitiation from the half height.
Now let us find the max. height it will travel from the half height.

h= (u^2)/2g = (10^2)/2*10 = 5
This is half the height. Then the complete height will be 10 m.
That is B option.

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