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Mechanics

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5 Dec 2008 12:43:16 IST

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Motion in one dimension

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A partical starts from rest in a straight line with acceleration f. The accelaration becomes 2f after time t, becomes 3f after time 2t and so on............... Find the velocity at the end of time nth and the total distance covered.

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VARUN RAJ

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Joined: 16 Mar 2008

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5 Dec 2008 17:18:03 IST

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nice sum dude acc at time t= f+ft where f is the time

v=adt = =

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Priyesh

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5 Dec 2008 18:18:05 IST

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velocity of particle at time t = ft

at time 2t = ft + 2ft

at time 3t = ft + 2ft + 3ft

at time nt = ft + 2ft + 3ft + ...... + nt

so velocity at time nt = n(n+1)/2 * ft

distance travelled = integral zero to t (n(n+1)/2 * ft) dt = n(n+1)/4 * ft^2

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