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Mechanics
17 Sep 2007 20:05:25 IST
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Nivedh Iyer
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17 Sep 2007 20:08:40 IST
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wat r the answers ????????????????????????????//
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21 Sep 2007 20:10:30 IST
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a=3-2t
but a =dv/dt
dv/dt=3-2t
dv=(3-2t)dt
integrate u will get it as
v=3t-t^2+u
where u is intial velocity
but v=dx/dt
dx=(3t-t^2+u)dt
integrating u will get it as
x=(3t^2)/2-(t^3)/3+ut+x(0)
where x(0)
is intial position
at t=0 we have it as x(0)
at t=5we get x=75/2-125/3+5u+x(0)
but given at t=5 x=x(0)
equate and u get u=5/6
satisfied???
but a =dv/dt
dv/dt=3-2t
dv=(3-2t)dt
integrate u will get it as
v=3t-t^2+u
where u is intial velocity
but v=dx/dt
dx=(3t-t^2+u)dt
integrating u will get it as
x=(3t^2)/2-(t^3)/3+ut+x(0)
where x(0)
is intial position
at t=0 we have it as x(0)
at t=5we get x=75/2-125/3+5u+x(0)
but given at t=5 x=x(0)
equate and u get u=5/6
satisfied???
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