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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Dec 2006 20:01:56 IST
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A string with one end fixed to a rigid wall is passed over a smooth
massless pulley at a distance of 2m.A point mass M=2kg is suspended
at a dist of 1mfrom the wall.A small mass m=0.5kg is attached to the free
end of the string.Find the speed with which M hits the wall when the
system is released from rest.g=10 m/s?
(Ans:-330 cm/s)
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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24 Dec 2006 22:13:35 IST
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Hey conservation of energy best solves the problem. Deal it with conservation of energy to enjoy the feel of solving it by your self. DO REMEMBER TO APPLY CONSTRAINT EQUATION. m ALSO HAS A VELOCITY .
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Praveen kumar gorakavi
Hyderabad.
gorakavipraveen@gmail.com |
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25 Dec 2006 14:43:42 IST
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Can anyone answer this??????????
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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25 Dec 2006 16:26:22 IST
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Plz solve this for me.......
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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26 Dec 2006 20:35:24 IST
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Deat Ananth
I am unable to visualize the problem.
Can u please send the diagram for the porblem
Or just quote the reference to the administrator. We will surely help u.
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The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
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26 Dec 2006 22:05:12 IST
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We will use conservation of energy for the system of masses. The potential energy lost by the M is given by Mg (1) and the potential energy gained by m is given by mg (h). Where h is given by h = Ö5 - 1. Let the two masses M and m have velocities v1 and v2 respectively. Then using conservation of energy Mg (1) - m g h = 0.5 (M v12 + m v22 ) Also v1 sin q = v2 Where sin q = 1 / Ö5.
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