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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Nov 2007 11:23:29 IST
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why does bulk modulus of a gas depends on the process the gas has undergone?
is there any proof along with ur explanation
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Nov 2007 11:39:21 IST
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tats simple common sense logic.... i dont know any proof ..sry if u cme across any such proof .........plz nudge me.
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om namoh narayana.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Nov 2007 11:59:08 IST
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Hello, I actually do not get your question so trying to explain it to you. Bulk Modulus: When a solid or fluid (liquid or gas) is subjected to a uniform pressure all over surface,such that the shape remains the same,then there is a change in volume. The Force per unit area applied uniformly over the surface of the body is called as "Normal Stress". The change in volume per unit volume is known as "Volume- Strain". The Ratio of "Normal stress" to "Volume Strain" with the elastic limits is called as "BULK MODULUS". It is denoted by "K" K = FV/A V Now as per my explanation given above it is understood that the "Bulk Modulus" depends on: "The process that the gas undergoes"  Hope you find it useful. Rate me if useful. Cheers!!!!!!!!@@@!!!!!!!!!
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Always available for help !
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Be damn serious for Questioning a weak one.
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B=- dP/(dV/V) now the relation bw dp and dV/V depends on the process
for a process PV^x = constant, dP/dV = -xP/V
so clearly, Bulk modulus of a gas depends on the process
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Nov 2007 13:11:03 IST
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Perfect rhd. Shiva you know gases folow ideal gas equation. Apply definition of bulk modulus to ideal gas and you will find that it is path dependent as rhd has done
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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