physics chemistry maths science forums
become expert I help I sign up I login
refer a friend - earn nickels!!   
 advanced
 
Home
Ask & Discuss Questions
Study Material
Experts Zone
Hang Out!

Ask & Discuss Questions with Community & Experts

Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board experts Expert Question: physics
Forum Index -> Mechanics like the article? email it to a friend.  
Author Message
avinash_science (6)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [3 rates]

avinash_science's Avatar

total posts: 11    
offline Offline
how do we get the value of gravitational constant.
    
gopi_mith (106)

Cool goIITian

Olaaa!! Perrrfect answer. 18  [26 rates]

gopi_mith's Avatar

total posts: 79    
offline Offline
The value of G can be determined experimentally using the famous CAVENDISH EXPERIMENT:
A bar AB is taken which is suspended from a rigid support by a fine wire. the bar has two small lead spheres attached at its ends. now two large lead spheres are brought close to the small ones by equal and opposite forces.
there is no net force on the bar, but a torque acts which is equal to F times the length of the bar, where F is the force of attraction between a big sphere and its neighbouring small sphere.
Due to this torque the suspended wire gets twisted till such time as the restoring torque of the wire equals the gravitational torque
if $ is the angle of the twist of the suspended wire, the restoring torque is proportinal to $ and is equal to T$ where T is the restoring couple per unit angle of twist.
T can be measured independently by applying a known torque and measuring the angle of twist.
the gravitational force between the spherical balls is the same as if their masses are concentrated at their CENTRES.
thus if d is the separation between the centres of the big and its neighbouring small sphere, with M and m as their masses, the gravitational force between the big sphere and its neighbouring small sphere is,
F=G(Mm)/d^2
if L is the length of the bar AB, then the torque arising out of F is FL.
At equilibrium,this is equal to the restoring torque.
Hence,
G(MmL)/d^2= T$.
Observation of $ thus enables one to calculate G from this equation.
this experiment was later refined and the accepted value of G is 6.67x10^-11 Nm^2kg^-2

BE THE CHANGE WHICH YOU WANT TO SEE IN THE WORLD......-M.K.GANDHI(THE ONLY HUMAN IN THIS WORLD)
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
ac (222)

Forum Expert Scorching goIITian

Olaaa!! Perrrfect answer. 38  [54 rates]

ac's Avatar

total posts: 243    
offline Offline
Hi,
Gopi has amply described the practical experiment to determine the value of gravitational constant in the laboratory.

Hope this answers your query.

All the best.

IIT Delhi, Batch of 2001
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Mechanics
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya