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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:36:05 IST
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The momentum of a particle varies with time  where A and  are constants. The K.E. of the particle increases at a rate of 1.  2.  3. 4. zero |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:42:24 IST
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3
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:51:23 IST
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howz dat??
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:55:00 IST
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brrrrrrr. that's wrong sorry let me try again.... everytime i'm getting a different answer
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:58:50 IST
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a= dp/dt= (Acoswt) i-(Asinwt) j ie net force F=ma is  to the motion hence (D) Zero are bhai simply uniform circular motion ki eq di hui hai in which KE remains constant  he he he !
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My name is Arnav.
Hoping we'll meet in IIT next year ! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 13:59:30 IST
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ya arnav i think ur xplaination is rite
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 14:06:21 IST
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Is the answer (4), i.e zero ?
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______________________________________________
Siddhant Shah
The trouble with doing something right the first time is that nobody appreciates how difficult it is.
You can't control the wind, but you can adjust your sails.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 14:10:12 IST
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p = Asinwt i + Acoswt j dp/dt = F = Awcoswt i - Awsinwt j so F.p = 0 ( . denotes dot product ) => force & momentum vector are perpendicular to each other hence force is perpendicular to direction of velocity hence no work is done by the force so there is no change in kinetic energy hence ans is zero = D)
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 14:13:48 IST
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yes ...answer is zero Thanks !!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 14:18:36 IST
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Re:physics
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______________________________________________
Siddhant Shah
The trouble with doing something right the first time is that nobody appreciates how difficult it is.
You can't control the wind, but you can adjust your sails.
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