IIT JEE , AIEEE Forum - Physics , Mechanics

anil_direct

I wanted the solution of H C Verma, Fluid Mechanics.

Question No's are 9, 10 & 11.

Thanking u in anticipation.

Admin

Hi Anil,

You can ask only one question in one topic.

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~forum administrator

anil_direct

Plz give me the solution to problem no. 10

Admin

Dear Anil,

The query seems to have missed out in the process. Will be answered shortly. thanks for your patience

~forum administrator

cvramana

Answer to Q.No 9 H.C.Verma.

Buoyant Force acting on the ornament is

Wt. In air - wt. In water = 36 - 34 = 2 grms.

Also buoyant force is the volume of the solid immersed x density of the liquid.

Therefore 2 = (36 - m ) / 19.3 + ( m) / 8.9

Which gives the value of 'm' where m is the mass of copper mixed.

Answer to Q.10 of H.C.Verma

Let the volume of the cavity be 'V'

Therefore Volume of the solid immersed + V = buoyant force / density of liquid.

Considering density of water =1 grm / cc.

Then 2 = (36 / 19.3 ) + V

Which gives the value of 'V'

Answer to Q.11 of H.C. Verma.

The equation for the equilibrium of the metal piece is

N + F = m g ------------------ (1)

Where F is the buoyant force and N the normal reaction.

F = mg x density of the liquid / density of the solid = mg / 8

Therefore

N = mg - F = mg - mg / 8 = 7 mg / 8.