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krithika rajendran's Avatar
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24 Aug 2008 19:46:55 IST
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PLEASE ANSwer THIS QUESTION BASED ON KINEMATICS......RATES FOR SURE!!
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 A Cannon was elevated at an angle of 15o, throws a shell with muzzle speed of 196m/s. Due to air resistance the range decreases by 100mm.what is the observed range?


 


please give me a answer with detalied solution. rates for sure.


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Karthik M's Avatar

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24 Aug 2008 20:35:47 IST
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See, theoritical range = \frac{u^2 sin2\theta}{g} = R


Observed range will be R - 100mm.


 


 


 


 

gauravtargetsiit's Avatar

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24 Aug 2008 20:35:52 IST
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use the formula
R= u^2sin(2theta) / g
where
u=muzzle velocity of shell
theta= 15degree
g=9.8m/s^2

and then subtract 100mm from it

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Joined: 10 Oct 2007
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25 Aug 2008 14:13:13 IST
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range R= {u2 sin(2*theta)}/g



Given data:



2 x theta = 2 x 15 = 30 degree; u = 196m/s, g = 9.8 m/s2







substituting,



R = {(196)2} x (Sin30)/9.8



= 1960 m



Observed range = R - 100mm



= 1960 - 0.1



= 1959.1m ........................ ANSWER




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