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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: please solve this numerical
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rahulsharma3154 (44)

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two trains each of length 100m moving in opposite directions along parallel liines meet each other with speed 50 km/hr & 40km/hr if their accelerations are 30cm/sec sq & 20 cm/ sec sq    find the time they take to pass each other

if you donot face difficulties in life then you are moving on the wrong path--albert einstein
    
saarika (172)

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is the ans 3.85 seconds
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rahulsharma3154 (44)

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can you tell me the procedure to this

if you donot face difficulties in life then you are moving on the wrong path--albert einstein
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lonewolf07 (372)

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http://www.goiit.com/posts/list/community-shelf-black-holes-18671.htm

visit n rate

thanx

Hi..........i m a dunce!! just kiddin!!
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sankydreams (949)

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dude is sarikas answer correct?

Put your hand on a stove for a minute and it seems like an hour. Sit with that special girl for an hour and it seems like a minute. That's relativity.
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sankydreams (949)

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look u will have to use the concept of relative velocity here
since the trains r moving in opposite dir add the velo
50 + 40 = 90km/hr= 25m/s

add the accn also 30 +20=50cm/s=1/2m/s

now dist = 100m
accn = 1/2 m/s
initial velo = u = 25m/s

use second eqn of mn to get the time

correct me if i m wrong
rate if u like my efforts...

Put your hand on a stove for a minute and it seems like an hour. Sit with that special girl for an hour and it seems like a minute. That's relativity.
-Albert Einstein

Generally people who take the piss out of other people hang around in groups of five, because they have a fifth of a personality each.
- Eddie Izzard

It's my life
And it's now or never
I ain't gonna live forever
I just wanna live while I'm alive
-Bon Jovi

By the time a son realizes that his father was probably right, he has a son who thinks he is wrong.
-Anonymous
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priyesh (1584)

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hi
see
see let the name of the trains be A(with 50km/hr) & B(with 40km/hr)
now since they are moving in opposite directions therefore velocity of train A w.r.t B = 50+40 = 90km/hr = 25m/sec
similarly acceleration of A w.r.t B will become 0.3 + 0.2 = 0.5m/sec^2
therefore it now becomes a case in which train A is moving with speed of 25m/s
& acceleration of 0.5m/s^2 has to overtake a stationary train B
therefore it's also clear that train A needs to travel 200m to cross train B
therefore using
s = ut+ 1/2at^2
200 = 25t + 1/2 * 0.5 * t^2
solve for t to get the answer

"Imagination is more important than knowledge."
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rahulsharma3154 (44)

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excellent concept priyesh

if you donot face difficulties in life then you are moving on the wrong path--albert einstein
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spideyunlimited (3007)

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yes gud work priyesh

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tarun_896959 (0)

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Given:
    Two trains move with velocities 50 km/hr and 40km/hr. They move with velocities 30cm/s^2 and 20 cm/s^s.
To Find:
      The time taken to cross.
SOLUTION:
    30 cm/s^2 = (30/100)m/s^2 = 0.3 m/s^2
     20cm/s^2 = (20/100)m/s^2 = 0.2 m/s^2
The acceleration of a body is given by a=dv/dt, dt=dv/a.
 
dt=[(50-40)km/hr] / [(0.3-0.2)m/s^2]
   = [10km/hr] / [0.1m/s^2]
   =[10*5/18 m/s] / (0.1m/s^2)
   =[25/9 m/s] / [1/10 m/s^2]
   =[(25*10)/(9*1)]. (m*s*s)/(m*s)
   =(250/9) s
   = 27.7778 s
Hence the time taken by the trains to cross each other is 27.7778 seconds.
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Omi (70)

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use relative velocity ur soln size gets reduced.... k see sit on train B say moving wit a speed of 40km/s.... so the train B is nw at rest kk..... nw train A dosnt move wit a speed of 50 bt wit a speed of 50+40= 90km/hr.... nw do the same exercise for their accelerations....k... nw use simple kinematics to gt the answer the asnwer comes out to be...3.856 secs.....
 IF U LIKE IT THEN PLZZZ RATE ME....!!!
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prathyu (53)

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very good explanation priyesh.

A man would do nothing if he waited until he could do it so well that no one would find fault with what he has done ------CARDINAL NEWMAN
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