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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Pleaz help...Too tough for me!
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akhil_o (2704)

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A triangular wedge of mass m and side length 2R(equilateral) is moving with constant velocity towards sphere (mass m) fixed to inclined plane(60 degrees).
After elastic collision, the wedge returns without any rotation.
The wedge is in contact with the sphere for time T, in which it experiences constant force F
Neglecting friction, find the normal force exerted by plane on wedge
 
PS i hav the soln...didn't understand that either..its long and after some time i'll post it.try till then!
Thanx


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akhil_o (2704)

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Click on figure and download for clear view

" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
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akhil_o (2704)

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The options are
 
A)  1/2{ mg+ 4/33(mv/T)}
 
B)  { mg+ 4/5(mv/T)}
 
C)  { mg- 4/3(mv/T)}
 
D)  1/2{ mg+ 4/3(mv/T)}
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veena001 (10)

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Its the last option...........
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akhil_o (2704)

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How?

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veena001 (10)

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cuz when the wedge is in contact with the sphere for time T, in which it experiences constant force F, tangent of certain force ( you may calculate ) will be taken into consideration , but when the wedge goes back in the opposite direction ( minus of minus is +ve ...you can see in the last option, so option C is wrong  ), cos of certain force will be taken into account ( so options A and B are wrong) So I am 99.99999 percent sure last option is correct. The angle of sliding is given 60 degrees . So tan 60 is root 3 and cos 60 is 1/2 ...both are there in the last option , taking the same reference fame into consideration .
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karthik2007 (3349)

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vague question... what is v?

Will nip in at times to solve problems :)
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T_T (7)

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draw the snap for the time of contact.............
conserving momentum....
Fsin60 * T = 2mv

normal force produced due to sphere=Fcos60
tot narmal=Fcos60+mgcos60

"iitian inside"
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