IIT JEE , AIEEE Forum - Physics , Mechanics - plot the graph between its kinetic energy and time

prakhar

"a particle of mass 'm' is released from a certain height 'h' with zero initial velocity. it strikes the ground elastically. plot the graph between its kinetic energy and time till it returns to its initial position."

plzzzzzzz help us and tell the steps how to deal with such type of questions

~prabhu

puneet

Hey chk out the answer posted by rahul.a on the follwing link:

http://www.goiit.com/posts/list/51.htm

ayush007

lets , start from the equations----
when the partical is coming down,
v=gt ---------------1

due to elasticcollision ,its velocity changes from +ve to -ve,but ,k.e not changes , before & after collision,means the magnitude of velocity remains unchanged even after collision....

kinetic energy=1/2(mv^2)=1/2m(gt)^2.
now as, we know , m & g are the constants, we take 1/2mg^2=x;
then kinetic energy = xt^2.
therefore,,
K.E.=xt^2
IT IS A UPWARD PARABOLA,which is like, y=kx^2 curve.
the max. k.e.(1/2m(gt)^2) . (corresponding to t=(2h/g)^1/2 and symmetrically ,it goes down then after ,to attend value of k.e=0.

please ,think about it carefully, you 'll surely benefit from this....

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