Home » Ask & Discuss » Physics. » Mechanics « Back to Discussion

Mechanics

Hot goIITian

Joined:	9 Sep 2007
Post:	130

19 Sep 2007 18:59:48 IST

0 People liked this

527

plz ans my ques

None

hc verma

vol1

pg82

q-33

Share this article on:

Comments (2)

Paloma Sodhi

Cool goIITian

Joined: 8 Jun 2007

Posts: 42

19 Sep 2007 19:30:46 IST

Like 1 people liked this

Here ,

using FBD for M,

Mg -T = Ma .................(1)

Now considering the wedge and the block to be a single object of mass (m+M') ,

using FBD,

(m+M')a = T

=> Mg-(m+M')a = Ma (putinng value of T in 1)

=> a = Mg/(M+m+M') .................(2)

Now since the wedge is accelrating towards right (horizontally), the block of mass m will experience a pseudo force in a horizontally backward direction( i.e. PF= -ma) ..

Resolving the pseudo force , the component parallel to the inclined plane is macos

Now since the block of mass m is not moving ,

=> macos

= mg sin

=> acos

= gsin

Now substitute value of a from (2) , to get the value of M ..

Hope this helps .. cheers!!

Mudit Jain

Forum Expert

Joined: 11 Aug 2007

Posts: 60

21 Sep 2007 11:24:06 IST

Like 1 people liked this

whenever u ask ny ques den plz write full question.

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team