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Mechanics

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5 Apr 2008 17:01:07 IST

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plz solve

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a solid sphere of mass m and radius r is free to roll over an inclined surface of a wooden wedge of mass m.wedge lies on a smooth floor .when system is released from rest find frictional force acting between sphere and inclined surface.

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namrata mishra

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6 Apr 2008 09:23:26 IST

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someone please solve yaar.........

namrata mishra

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6 Apr 2008 10:56:03 IST

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koi to solve karo.......

namrata

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6 Apr 2008 11:06:29 IST

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frictional force will be equal to the torque acting o the system=Iw.where w is the angular speed

namrata mishra

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6 Apr 2008 12:05:27 IST

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plz solveit

namrata mishra

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6 Apr 2008 15:37:42 IST

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no one there to solve?????????????????

Soumen Goswami

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Joined: 10 Apr 2007

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13 Jul 2008 11:56:29 IST

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Let a' be the acceleration of the sphere's cm wrt the wedge. It will be directed down the plane. Let a be the acceleration of the wedge. Let be the angular acceleration of the sphere. Now as the sphere is observed in the reference frame of the wedge, there is a pseudo force ma on the sphere directed opposite to the acceleration of the wedge.

If N be the normal force between the sphere and the wedge,

N=mg cos - ma sin and Nsin = ma

This gives a = gsincos/(1+sin²)

Now, for no slipping a' = R

a cos + g sin - (f/m) = (5f/2m)

Substitute the value of a and find f

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