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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 23:59:42 IST
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when a projectile is launched on an inclined plane with inclination beta and initial velocity vector makes an angle of alpha with horizontal is it possible 2 apply R,H,T formula taking the coordinate system along the incline(by making some modifications like taking g as g cos(beta) etc)??? If yes please demonstrate
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 01:59:31 IST
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Re:Inclined plane projectile
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 02:03:43 IST
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Dude, Look at the above diagram: Here, 1) Time to reach at H = ½ T 2) X1 = X2 = R/2 3) U = V 4) Angle B = Angle @ Now check out the inclined plane diagram below
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 02:05:02 IST
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Re:Inclined plane projectile
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 02:08:47 IST
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Now, Look at the above diagram: Here, 1) Time to reach at H = ½ T 2) X1 not= X2 not= R/2 (but X1 > X2) 3) U > V 4) Angle B < Angle @ 5) Acceleration along X is not constant
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 02:25:37 IST
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So P90, Look at the above diagrams and try to prove the T, R & H formulae for inclined plane. You will find T = 2 U SinB/ g Cos& H = U2 Sin2B/ 2g Cos& (as you said, ie just replace g) But, for Range you will get a complicated expression, R = 2 U2 SinB . Cos(B+&) / g Cos2& Nudge me if you have any query regarding this
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 22:50:57 IST
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People, somebody has given me a red mark for this answer?. Help what should I dooo????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 22:59:19 IST
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sorry mate you got boinked for a honest effort. but whoever did it you took your "NOT HERE FOR RATES" line too literally.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2007 23:18:26 IST
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Hey I donno who the new person is !!! and I am sure he must have dont it by mistake!!! Camon people! if you dont want to salute my efforts, at least dont gimmie a boink!! A boink indicates a bad job and worthless efforts! I m here to help!!! and my efforts are not worthless
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2007 00:20:23 IST
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What nonsense is this ? How can anyone get boinked for this. I think the boinks are approved before coming in effect ? How can that reason be approved ?
Indzee...nudge the admin. He should remove your boink. That is just not right.
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http://14-69-8.blogspot.com
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2007 00:26:05 IST
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@ P90 Dude To derive the range formula, Just the thing you do is, >>Use the second kinematical equation along the x direction on inclined plane, >>Substitute the value of Time (T) in it? >>After that take 2U2 SinB /g Cos2& common, >>You remain with Cos& CosB ? Sin& SinB inside the brackets which you can write as Cos(B+&) >>Therefore you get the final Equation as, R= 2 U2 SinB . Cos(B+&) / g Cos2& Hope you got it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2007 00:52:13 IST
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Thanks Roony for everything, but how can I contact admn to remove that boink.
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