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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jan 2007 22:19:42 IST
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Solve - Two particles are projected from a point at the same instant with velocities whose horizontal and vertical components are u1,v1,u2,v2 . Find the The interval b/w their passing through the other common point of their path . Pls post the answer as soon as posible !!!!!
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Umang |
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28 Jan 2007 23:56:01 IST
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hi,
just a hint as i dont have enough time to give the entire soln.assume after some time t the second one crooses after the first and the horzontal and veritcal ht is the same for both i mean u can just calculate by taking t .
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1 Feb 2007 22:48:40 IST
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i am answering ur qus pls wait
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1 Feb 2007 22:55:01 IST
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see u start taking everything u have and start writin all the equatins
and then u assume the first particle takes t1 time and the second particle takes time t2 to reach the same pt .
then aply
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1 Feb 2007 23:02:17 IST
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u1t1=u2t2 then v1t1 - 0.5gt12 = v2t2 - 0.5gt22 in the second eqn substittute t1= u2t2 / u1 in the second eqn and ull get t1 and then from first eqn get t2 and then t2-t1 is ur answer
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1 Feb 2007 23:04:27 IST
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i hope im clear
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2 Feb 2007 11:52:08 IST
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ans-2/g*(u(1)v(2)-u(2)v(1))/u(1)+u(2)
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2 Feb 2007 21:24:04 IST
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Hi Kusum , Pls explain how you got u1t1=u2t2 ?
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Umang |
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