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22 Sep 2011 16:13:09 IST

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Projectile Motion

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A particle is projected up the inclined such that its component of velocity along the inclined is 10 m/s.Time of flight si 2 sec and maximum height above the inclined is 5m.The initial speed of projection is

Comments (2)

Juhi Sharma

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Joined: 22 May 2009

Posts: 2467

18 May 2012 12:31:30 IST

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2*u*sin@/gcosB=2

u^2sin^22/gconB=5

usin@=5

Ucos@=10

speed is 11.18m/sec

karan gupta

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Joined: 26 Mar 2009

Posts: 38

18 May 2012 16:52:15 IST

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Uy=gcos@ at max height t=1sec Sy=Uyt+1/2Ayt^2=55=gcos@u=sqrt Ux^2+Uy^2 =sqrt 125=5sqrt5 this the correct answer i m damn sure!!

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