IIT JEE , AIEEE Forum - Physics , Mechanics - pulley-wedge problem

MANUSUN

a system shown in fig, blocks 2&3 kg are at rest.coefficient of friction getween 2 kg & incline is

(a)2/?3 (b)1/2

(c)1/3 (d)can't be calculated

ANSWER IS (d)can't be calculated WHY???????

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my answer was

after resolving & equating x & y components along the plane,

we have f + T = mg sin30

FF m = 2/?3 i.e.(a)

umang

Hi manasun ,

well , I am getting 2/sqrt 3 . Pls tell me how it cant be calculated when u get it !

kusum

hi
the answer is definetely cant be calculated bcoz at that point might there is even lessser frictional force than the max frictional force .

if it was mentioned that even with a light impulse under this condition would move the blocks then probably u resove all the forces and get the answer .i hope im clear . any doubts please ask

umang

Hi Kusum ,

Yes , u r right !!!

Nothing is mentioned in the question , hence it cant be calculated !!!

umang

Hey Kusum ,

u had replied to the Projectile question I had asked once , can u pls give me the complete solution as i am not able to get it !!!!!

I shall be really thankful to u !!!

Thanks

kusum

could u pls tell me the ques i can search in my posts and just copy n paste ull get the sol in seconds. pls

umang

Hey Kusum ,

U can open my account and see my bookmarks . Its with the name "projectile'

umang

I hope u got it !!!!!!!

kusum

ya ill answer it thr

bhupesh

Dear

It can certainly be calculated but you can't calculate coefficient of static friction but coefficient of friction in the given situation

T=m'g

=m'g -mgsin theta /m

ashish040191

3g-T=ma. a/q bodies r in equil. ther4 30-T=0 _(i)

T - 2gsin30-2mugcos30=0.ans is 2/1.732

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