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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Feb 2008 19:03:29 IST
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ques .39 hc verma SHM
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7 Feb 2008 18:03:27 IST
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no ans????????????
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7 Feb 2008 20:50:47 IST
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posted one long soln some time back.so am in no mood to post another long soln
i'll just explain the method. if you don't get the answer ask me to post it.--
first find velocity of com=(R-r)w where w=omega=ang velocity
taking theta as angle made by the line joining sphere and centre of circle(R) at some pt with vertical,find total energy at that pt where
potential energy=mg(R-r)(1-costheta)
put total energy=const
then take derivative with respect to time--
put sintheta = theta
final eqn is-- alpha/theta=omega square=5g/7(R-r) [omega=omega of shm0
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