IIT JEE , AIEEE Forum - Physics , Mechanics

prakhar_galaxy

All surfaces shown in fig are smooth .System is released with the spring unstretched.In equilbrium ,compression in the spring will be:

( nothing is fixed in the ques except spring which is fixed from wall)

Plz do it with energy conservation coz i am not able to do it with energy conservation

answer is (mg/k)

this answer is 100% correct u can check it by solving this ques from newton's laws

fig is below

plz click on fig & open it then u will see clear picture here it is not clear

nandonachi

fig not clear even after downloading it

deepak_agarwal

well the figure is clear and i have verified ur ans by doing using force diag..now tell me y do u want to do it using energy conservation...do u noe how tough u will make this otherwise simple prob...to give u an idea...rod will fall down by a height h and with velocity v and hence push wedge towards right with velocity u and thus compress spring..velocities will be obtaine d by momentum balances

prakhar_galaxy

actually bhaiya i am getting a diff answer by solving it by work energy
and i know it is not possible to get diff answers frm diff methods dats wny i asked
secondly in exam no one is going to ask us dat by which method we hav solved the ques
so i think dat i shud be able to solve the ques from every method possible
plz now solve it by energy principle & post the solution

prakhar_galaxy

hey any expert plzz explain it
plzzz

prakhar_galaxy

hey any expert plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

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