Home » Ask & Discuss » Physics. » Mechanics « Back to Discussion

Mechanics

Blazing goIITian

Joined:	11 Apr 2009
Post:	672

18 Mar 2010 19:56:04 IST

0 People liked this

354

question is abt resonance in open ended and closed pipes

Physics , Mechanics , Kinematics , Newtons laws CircularMotion , Work Power Energy collisions , Rotation , Gravitation , Simple Harmonic Motion , Fluid Mechanics , Materials Wave Sound , Super Position , units dimensions , com momentum , shm , wave sound

now .....i know dat a displacement ANTINODE is formed at the end ( or ends in case of both side open pipe)....and antinode is formd at the closed end......but i wanna know why does a pressure node get formed (at open end) and antinode( at closed end).......do not tell me dat dis is because displacement function is the opposite of pressure function ( sin and cos).........but give me a solid reason and if possible a proof.......secondly if there is a second harmonic then again a pressure node is formed in between...y ???.......a displacement node is formed in open ended pipe ( both side)...in between .....why|??????

Share this article on:

Comments (8)

G.Reshma begum

Cool goIITian

Joined: 28 Feb 2010

Posts: 59

18 Mar 2010 22:26:27 IST

Like 0 people liked this

deltaP=-B(deltaV/V) =-B(duo y/duo x)

delta P=BKY₀COS(wt-kx)

. .

Blazing goIITian

Joined: 11 Apr 2009

Posts: 672

18 Mar 2010 22:28:48 IST

Like 0 people liked this

evry1 knows these eqns....i have asked for sumthng else!!!!!!......btw in first eqx.. it is d(displacement)

G.Reshma begum

Cool goIITian

Joined: 28 Feb 2010

Posts: 59

18 Mar 2010 22:40:37 IST

Like 0 people liked this

plz once see d kundl's tube experiment u may be getting some info

silent killer

Blazing goIITian

Joined: 15 Nov 2009

Posts: 564

19 Mar 2010 14:01:30 IST

Like 0 people liked this

hi friend ....u have mentioned that the displacement is node at the open ends but it is actually anti node.am i right?

. .

Blazing goIITian

Joined: 11 Apr 2009

Posts: 672

19 Mar 2010 14:04:09 IST

Like 0 people liked this

yesss...let me edit it !!!..missed it .......well do u noe the answer???

silent killer

Blazing goIITian

Joined: 15 Nov 2009

Posts: 564

19 Mar 2010 14:15:05 IST

Like 0 people liked this

if what i told is right then i have an explanation.when the disp is antinode ,the particles will be vibrating with largest amplitude.as a result the pressure decreases (more empty space between the molecules. ) and is least at displacement node.when the disp is node there the molecular amplitude is least.and everyone is gonna crowd together causing pressure antinode!

. .

Blazing goIITian

Joined: 11 Apr 2009

Posts: 672

19 Mar 2010 14:19:31 IST

Like 0 people liked this

THIS MAY ANSWER MY FIRST QUESTION..............BUT WHEN WE TALK ABT FIRST OVERTONE AND SO ON THE NO OF RINGS INCREASES.......SO HOW COME THERE IS A DISPLACEMENT NODE IN BETWEEN????? ( IN A BOTH SIDE OPEN PIPE) ......AND SO ON ..........( this was just an example, there are both disp nodes and pressure nodes in both pipes).............is it just because theory says so?

silent killer

Blazing goIITian

Joined: 15 Nov 2009

Posts: 564

19 Mar 2010 14:27:00 IST

Like 0 people liked this

IT IS BECAUSE IT IS JUST VIBRATING IN THAT FASION. I THINK IT IS NOT JUST STATIONARY LIKE A POINT, BOTH THE WAVES ie,THE INCIDENT AND THE REFLECTED WAVES ARE MOVING SIMULTANUSLYIN THE OPPOSITE DIRECTION AS A RESULT OF WHICH AT THAT PARTICULAR POINT ,THE SUPERPOSITION OF THE TWO WAVES ARE ZERO!

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team