I have given you the free body diagrams of the sphere andthe plank in the figure below:
Let "a1" be the acceleration of the plank And
Let "v1" be the --Velocity--of the plank.
Then we have:
F = ma1 = -umg
a1 = -ug
And
v1 = (-ug)T
v1 = -ugT
For the sphere,
acm = ug
and
vcm = ugT
The torque acting on the sphere about the centre of mass
is given by:
= umgr
I
= -umgr
= -umgr
I
Here,
I = (2/5)mr2
Therefore we will get:
= -5ug
2r
Now,
wt = (wo - 5ugt)
2r
For rolling,
V1 = Vcm - wt*r
V1 = Vcm - (wo - 5ugt)r
2r
After solving the above expression we will get:
t = 2wor
9ug
Now the distance travelled by the plank is given by:
s1 = (1/2)(-ug)(2wor/9ug)2
s1 = -2wo2r2/81ug
Hope you find it useful.
Cheers !!!!!! @@@ !!!!!!! 