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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 20:30:01 IST
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in the figure shown the plank is pulled to right with constant speed v.if the cylinder doesnot sip then. angular velocity of cylinder is v/R??? T/F?? PLS EXPLAIN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:14:52 IST
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is it v/2R?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:17:49 IST
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Should be false
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 23:55:54 IST
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Arey, Why should it be "V/2R" There is no Relative slipping between Cylinder and Block. So the velocity will not change. V = R Therefore, = V/R. Hence it is true. Cheers !!!!!!!!!!!!!!!! 
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Always available for help !
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 23:58:01 IST
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I was wondering about that... But what I did was, here the velocity of the point of contact is v, so velocity of center of mass will be v/2.
So, w = Vcm/R = V/2R...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 00:01:30 IST
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Hmm, I think you are right waterdemon. I think I made a grave mistake
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 00:33:52 IST
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i think it is false see for the cylinder to not slip on the plank the velocity of the bottommost point must be v in the right direction so that there is no relative vel. between the plank & cylinder. also due to constraint relation velocity of centre of mass of cylinder is v towards left so taking right direction as positive -v + rw = v => w = 2v/r
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 01:01:33 IST
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d answer 4 dis is v/r bcoz 4 no slipping there will b no relative motion 4 bw d point in contact wid d block and d block hence d velocit of d point of contact will b v
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 09:23:25 IST
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Yes priyesh is right. I forgot to take the sign conventions properly
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 10:46:02 IST
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hey it is true i have got it.... @ priyesh how u have taken -v + rw = v => w = 2v/r??? here -v in lhs is taken as the velocity of centre of mass....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 10:46:33 IST
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see my soln.... since the rope passes above the cylinder ,hence the velocit of point at the circumference due to rotation will be v,same as velocity of rope.... and for rotation v=rw =>w = v/r.. pls correct if i am wrong.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Dec 2007 10:47:47 IST
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See dude, its the sign convention. The CM moves to the left, but the bottommost point moves to the right.
The mistake I made was I simply wrote v+rw =v'
you have to assume one direction as positive and vice versa
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Dec 2007 07:30:39 IST
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hey how u have got the velocity of centre of mass as v, towards left?????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Dec 2007 08:19:04 IST
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w=v/r . Same as waterdemons reply. Its right
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Dec 2007 12:11:15 IST
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