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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: ROTATIONAL
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[Post New]31 Mar 2008 13:28:30 IST
    Subject: ROTATIONAL
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nishi.tiwari (179)

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Q
 A thin spherical shell of radius R is set into the rotation abt its axis at an angular speed   .This rotating  wheel is now placed on a rough surface (horizontal) wid its axis horizontal. Because of friction at the contact , thw wheel  accl  forward & its rotation .declerateas  till the wheel starts pure rolling on the surface .Find the linear speed of  the wheel after it starts pure rolling?????
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>

    
[Post New]31 Mar 2008 17:57:57 IST
    Subject: Re:ROTATIONAL
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nishi.tiwari (179)

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some1 plsssss solve this
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>

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[Post New]31 Mar 2008 17:59:32 IST
    Subject: Re:ROTATIONAL
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elastiboysai (2327)

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Conserve angular momentum abt lowermost point
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[Post New]31 Mar 2008 18:08:27 IST
    Subject: Re:ROTATIONAL
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annihilator (298)

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 elastiboysai is right ...here's the soln,
since the torque abt pt of contact is zero ang momentum is conserved abt tht pt
initial  ang momentum=2/3mr2
final ang momentum=5/3mr2'
.`. ' = 2/5
or linear speed v=2/5 r
Ajay Antony
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[Post New]31 Mar 2008 18:09:01 IST
    Subject: Re:ROTATIONAL
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elastiboysai (2327)

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Abt bottommost point net torque is zero
so u can conserve angular momentum abt lowermost point.
suppose inital angular veloc is
and final angular veloc is 0
I=I 0 +mrv
and once pure rollin starts v=r 0
plug in for I and solve
2/3mr^2=5/3mr^20
0=2/5
so v=2/50r
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