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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 12:06:25 IST
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A rod of mass m is supported by two parallel and vertical strings .If one of the strings is cut suddenly, calculate the tension in other string immediately thereafter.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 12:14:22 IST
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i m getting mg/2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 13:32:04 IST
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is it mg
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 13:50:04 IST
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is it 3mg/4
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 17:01:14 IST
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is it mg/2?
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 17:25:49 IST
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Its mg/4.
Consider the instant when the string is just cut and the rod is momentarily in horizontal position.
Applying Torque= I x Alpha about the point where string is connected to the rod
mgl/2 = ml2/3 x Alpha
Now , consider the acceleration of the COM where mg is acting at that instant to be a.
So, Alpha = a/(l/2) = 2a/l
Solve and get a = 3g/4
Put this in mg - T =ma to get T =mg/4
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