| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 14:43:28 IST
|
|
|
Question A body of mass M slides down an inclined plane & reaches the bottom with velocity v. If a disc of same mass rolls down the same inclined plane,what will be its velocity on reaching the bottom ? a. v b. v / 2 c. 2/3 v d. v / 2
|
|
|
|
|
|
|
|
Let the body be kept at height h
when body slides down
Mgh=1/2 Mv2
when disc of same mass rolls down
Mgh= 1/2 M v12 + 1/2 Iw2 => 1/2 Mv2 = 1/2 Mv12+1/2(1/2 Mr2)v12/r2 => v2 =v12+1/2v12 => v2=(3/2)v12
=>v1= (2/3) v
|
~ANSHUMAN
I was born intellegent, education ruined me. |
this reply: 15 points
(with 3 
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 14:54:28 IST
|
|
|
but if a disc rolls then there must be some friction so in the intial case also friction would have acted..........
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 14:56:15 IST
|
|
|
Consider the first body. Let the height of the inclined plane be h.
Using conservation of energy, we get
1/2mv2 = mgh.
which gives v2 = 2gh - (1)
Consider the sphere. The sphere has both rotational and translational kinetic energy. Its moment of inertia about its COG is mr2/2.
Using conservation of energy again, we get:
mgh = 1/2mv'2 + 1/4mv'2 (using v=rw for pure rolling)
This gives 3v'2 = 2v2
which gives v' =( 2/3)v.
Option C
|
Will nip in at times to solve problems :)
|
this reply: 15 points
(with 3 
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 14:57:11 IST
|
|
|
ohh... looks like anshuman got the reply a few minutes ago
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 14:59:54 IST
|
|
|
apurv. it is not necessary that there shud be friction. The disc can be set into rolling motion before it is set to slide down.
|
~ANSHUMAN
I was born intellegent, education ruined me. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 15:02:31 IST
|
|
|
ok ok silly doubt...... got it...............
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Nov 2007 21:24:08 IST
|
|
|
but even if friction does act....work done by friction in pure rolling is 0 so u can always conserve energy
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Nov 2007 21:24:44 IST
|
|
|
but even if friction does act....work done by friction in pure rolling is 0 so u can always conserve energy
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Nov 2007 21:25:28 IST
|
|
|
sry abt the double post...my bad
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Nov 2007 12:51:42 IST
|
|
|
*post edited*
|
padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....
PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
"YEH KIS PAGAL NE MERA QN. SOLVE KER DIYA"
I AM SERIOUS!!!!
EVEN SERIOUS ^ INFINITY
PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....
Shubham
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Nov 2007 13:11:59 IST
|
|
|
hey shubham work done by friction is zero in case of pure rolling because the bottommost point is at rest and hence friction does not act (so work done by it is zero)
|
"Imagination is more important than knowledge."
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Nov 2007 13:45:09 IST
|
|
|
@ johri anshuman even if u release the disc after setting it in pure rolling....it will not move without slipping if there is no friction...for pure rolling on the inclined plane friction must be there...what you are saying is true for a horizontal surface....
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|