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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 15:29:30 IST
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I just came across a pretty good problem in rotational motion, and I thoroughly enjoyed solving it. I thought I'd share the problem with you, and I hope you have fun solving it. The person who solves this should have understood rotational motion pretty well. So go ahead and test your understanding:
(It is not very difficult at all, just application of the concepts)
Problem : A sphere of mass M and radius R is moving on a rough horizontal surface, having coefficient of friction  . Find the time after which it will attain least linear velocity.
I will salute the correct reply 5 times. I will post the solution tomorrow morning/Today night if no one has managed the right answer (which i doubt as there are so many geniuses around)
Click on the image for best clarity. One more thing, the question is very clear, so dont ask me anything regarding the question.
Cheers!
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Will nip in at times to solve problems :)
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19 Nov 2007 15:34:33 IST
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Vo/(mu) g
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19 Nov 2007 15:36:23 IST
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Wrong. It is not that easy either!
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19 Nov 2007 15:52:48 IST
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Any other attempts?
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19 Nov 2007 17:52:19 IST
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No one is getting it?
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19 Nov 2007 17:57:11 IST
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1/2 m Vo^2 + 1/2 I.w^2 =  mg s s = 1/2 mg ( mVo^2 + 2/5 m R^2.w^2) ma = mg a = g appllying eqn. of motion we get s = Vo t - 1/2 gt^2 from above we can find t.... is it correct.
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19 Nov 2007 17:58:18 IST
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Hmm solve and tell me the final answer. Just the final answer.
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19 Nov 2007 17:58:43 IST
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I think you almost got it... but nevertheless, simplification is quite simple. So tell me what final ans u get
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19 Nov 2007 17:59:03 IST
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sorry i didn't have pen or paer here... tell me if i m correct..
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19 Nov 2007 18:02:34 IST
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Well you may be or may not be. You've got to solve and tell me. I too dont have a pen here. So when u solve it, post it here. Need not post the method. If its right, 5 salutes!
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19 Nov 2007 18:09:17 IST
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answer contains two terms??... one containing root..
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19 Nov 2007 18:33:54 IST
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well i have solved it without using pen or paper....so
is t = (Vo + Rw rt.2/5 )/ (mu) .g
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19 Nov 2007 18:36:47 IST
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plzzzzz say sumthing.....am i right or will have to go to the counter to fetch pen .
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19 Nov 2007 19:09:41 IST
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is the answer 2/7ug (v-wR)
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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19 Nov 2007 19:52:49 IST
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@rhd92 - can you make your answer more clear? Like what all terms are there in the numerator and denominator?
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