IIT JEE , AIEEE Forum - Physics , Mechanics

deep01

Is sin³

t is in S.H.M???

pls explain me?why or why not

yahiyafirdous

x=sin³

when

=2(pie)n where n=0, 1, 2.....

sin³

=0

when

=2(pie)n + pie/2

x=1

when

=2(pie)n - pie/2

x= -1

Hence it is SHM, with point of equilibrium at x=0

Amplitude x=1

KAB

No.The acceleration will not be proportional to displacement from the mean position which is the required condition.Acceleration is found by differentiating the equation twice.

rajat

KAB u r right .yahiyafirdous, u should keep all the requirments in mind

umang

Hey adarsh !

yes , I agree with you !!!

but this will hav periodic motion .

rao_prabhat

For a equation to follow periodic motion the following equation must the periodic motion the following equation must hold true:
a = -omega^2x where x represents the equation of the motion
to find the acceleration one has differentiate twice :
on differentiating two times we get:
a = 6omega^2sin(omega*t)cos^2(omega*t)-3omega^2sin^3(omega*t)
this equation doesn?t clearly is equal to = -omega^2x
Therefore the motion is not simple harmonic or periodic
---Hope this Helps
Prabhat
Give me your rate;

rao_prabhat

am expecting a good rate

rao_prabhat

soory the motion is periodic

rajat

of course the motion is periodic.one doesn't need rocket science to prove it.after all its just a sine function which is of course periodic.please give some reward for this simple solution of mine

KAB

Are you happy now rajat???

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