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Mechanics

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Joined:	17 Feb 2007
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18 Feb 2007 19:13:52 IST

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603

saturn

None

a saturn is 29.5 times the earth year. how far is saturn from the sun if earth is

1.50(10 into 10 upto 8 times)km away from sun?

ans- 1.43(10into10upto9times)

can we use cappelers law?

i want to know calculations&method

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Comments (4)

calculas

Cool goIITian

Joined: 10 Feb 2007

Posts: 74

18 Feb 2007 19:22:50 IST

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abhishek its easy use keplers 3 law
T^2 IS PROPORTIONAL TO a^3
LET T1 & T2 BE THE TIME OF REVO FOR EARTH
& SATURN . AND A1 &A2 BE RADIUS OF THEIR ORBIT
THEN
[T2/T1]^2 =[A2/A1]^3 PUT IN THE VALUES AND CALCULATE
29.5^2 = [A2/1.5]^3
A2=14.3 YOU HAVE DISPLACED THE DECIMAL POINT

abhishek punpale

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Joined: 17 Feb 2007

Posts: 28

18 Feb 2007 19:27:05 IST

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thanks.

Bipin Dubey

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Joined: 23 Jan 2007

Posts: 7942

21 Feb 2007 07:06:25 IST

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Kepler's 3rd law implies that T² is proportional to R³

Then (T_saturn/T_earth)² = (R_saturn/R_earth)³
=> 29.5² = (R_saturn/(1.5*10⁸))³
=> R_saturn = (1.5)(10⁸)(29.5^2/3)
= 1.43*10⁹ km

Truly Mittal

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Joined: 20 Feb 2007

Posts: 198

21 Feb 2007 17:34:18 IST

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@ abhishek

you can always use kepplers law coz its for planetary motion and not to b considered only for earth or its sattltes....so in any motion whose path is elliptical we can use kepplers law

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