physics chemistry maths science forums
become expert I help I sign up I login
refer a friend - earn nickels!!   
 advanced
 
Home
Ask & Discuss Questions
Study Material
Experts Zone
Hang Out!

Ask & Discuss Questions with Community & Experts

 Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board community Community Discussion Question: SHM
Forum Index -> Mechanics like the article? email it to a friend.  
Author Message
[Post New]17 Nov 2007 20:58:20 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
A particle of mass m is attached to three springs of equal force constant K as shown in figure.if the particle is pushed slightly against the spring which makes angle 45 and then released,find the time period of oscillation.

Salutes 100% gauranteed.
plzz give detailed solution stating how the spring are in parallel or series

    
[Post New]17 Nov 2007 21:18:18 IST
    Subject: SHM
[Up] View Post
madman (239)

Blazing goIITian

Olaaa!! Perrrfect answer. 33  [70 rates]
madman's Avatar
total posts: 486    
offline Offline
is the answer
2pi / root(K(2-root2))
science-
the most fundamental
the most eternal
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]17 Nov 2007 21:27:26 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
no its2pi rootm/2k
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
[Post New]17 Nov 2007 23:51:41 IST
    Subject: Re:SHM
[Up] View Post
aditya_arora04 (1077)

Blazing goIITian

Olaaa!! Perrrfect answer. 163  [294 rates]
aditya_arora04's Avatar
total posts: 1042    
offline Offline
2(pie)(3m/k)1/2    ??????????
My birthday is no ordinary day.

Its the day when i declared in my own voice,

I WILL NOT GO QUIETLY INTO THE NIGHT,
I WILL NOT VANISH WITHOUT A FIGHT,
I AM GOING TO LIVE ON,
I AM GOING TO SURVIVE,
I AM GOING TO GET WHATEVER I WANT.

I CELEBRATE MY BIRTHDAY, AS MY INDEPENDENCE DAY !!!!!!!!!
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 00:24:53 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
Somebody ans yaar.....plzzzzzzzzzz
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 11:26:06 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
Friends,this is an HCV sum yaar............
Common,i am in need of this..
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 11:34:13 IST
    Subject: Re:SHM
[Up] View Post
waterdemon (5140)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 944  [1154 rates]
waterdemon's Avatar
total posts: 1030    
offline Offline
Note:
Spring B = Y axis
Spring A = X axis
Spring C = Z axis (making angle 45 with x axis.)

Let "x" be the displacement of SpringC.

The displacement of A = (x)Cos(45) = x/2

Similarly,The displacement of B
=xSin(45)
=x/2

Now the forces acting on "m" in the displaced position of m
are:

Kx in the direction of Spring C.
Kx/2 in the direction of Spring B
Kx/2 in the direction of Spring A

Therefore the Net Force in the direction of Spring C

=Kx + [(Kx/2)2 + (Kx/2)2]
=2Kx.

Therefore,
m(d2x/dt2) = 2Kx

(d2x/dt2) = (2K/m)x

 = 2/T

= K/M

Therefore,

T = 2 (m/2K)

Hope you find it useful.
Rate if useful.

Cheers!!!!!!!!!!@@@!!!!!!!!!
Always available for help !

But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.







<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>







 this reply: 15 points  (with 3 Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 11:53:17 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
Therefore the Net Force in the direction of Spring C

=Kx + [(Kx/2)2 + (Kx/2)2]
=2Kx.
Yaar Kx and [(Kx/2)2 + (Kx/2)2] are in oppsite direction ..............
then how did u add them???
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 11:58:03 IST
    Subject: SHM
[Up] View Post
kishan12 (309)

Blazing goIITian

Olaaa!! Perrrfect answer. 59  [66 rates]
kishan12's Avatar
total posts: 365    
offline Offline
Sorry......................got it..............
Thanks a lotttttttttttttttttttt nikhil..........
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 12:06:03 IST
    Subject: Re:SHM
[Up] View Post
waterdemon (5140)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 944  [1154 rates]
waterdemon's Avatar
total posts: 1030    
offline Offline
Ok,
you got it...
Cheers!!!!!!!!!@@@!!!!!!!!
Always available for help !

But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.







<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>







 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 16:42:19 IST
    Subject: SHM
[Up] View Post
karthik2007 (3349)

Blazing goIITian

Olaaa!! Perrrfect answer. 591  [788 rates]
karthik2007's Avatar
total posts: 2585    
offline Offline
Can you explain more clearly how you resolved the displacements?
Will nip in at times to solve problems :)
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 18:30:23 IST
    Subject: SHM
[Up] View Post
kislay (1063)

Blazing goIITian

Olaaa!! Perrrfect answer. 187  [251 rates]
kislay's Avatar
total posts: 781    
offline Offline
yeah nikhil has solved it correctly.
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 18:37:16 IST
    Subject: SHM
[Up] View Post
madman (239)

Blazing goIITian

Olaaa!! Perrrfect answer. 33  [70 rates]
madman's Avatar
total posts: 486    
offline Offline
hey karthik its simple.
what u want is the forces on the block
so u need the individual displacements of each spring
when the spring C is stretched the other two have the same displacement ,whose net is in the direction of the line x=y
the spring B is in horizontal position so it would be stretched as much as the horizontal displacement of C.
hope u got it.
have a nice day
science-
the most fundamental
the most eternal
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]18 Nov 2007 19:44:38 IST
    Subject: SHM
[Up] View Post
karthik2007 (3349)

Blazing goIITian

Olaaa!! Perrrfect answer. 591  [788 rates]
karthik2007's Avatar
total posts: 2585    
offline Offline
Never mind... I got the solution myself. The mistake that i made was that I thought that the third spring is perpendicular to the plane of the paper
Will nip in at times to solve problems :)
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Mechanics
Go to: