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6 Feb 2009 10:38:44 IST

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SHM

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A particle in SHM has displacement of 0, 5 cm, 5cm at time 0, 1 s, 2 s resp.What is the amplitude????????

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Ashlesh

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Joined: 24 Jan 2009

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6 Feb 2009 11:05:00 IST

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since disp is same at 1 and 2 sec...particle will return to mean at t = 3 sec ...then period is 6 sec ...w = 2pie / 6 = pie/3....x = A sin ( pie/3)t...put x=5 at t=1....and get amplitude = 10/root3.........please rate if useful

shraman asa

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6 Feb 2009 11:18:38 IST

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let eqxn be of form AsinWt ......................AsinW = Asin2W ............(AS 5=5...lol)

sinW =2sinWcosW ..........................cosW = 1/2 .........................W=pi/3 ..................................

5=Asin(pi/3)

5=A(3)^1/2/2 ........................A= 10/(3)^1/2

Atul Mohan

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Joined: 24 Jan 2009

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6 Feb 2009 19:23:43 IST

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x=AsinWt........ 5=AsinW....5=Asin2W......DIVIDING, sinW=sin2W.......so 2cosW sinW = sinW.....so cosW=1/2........

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