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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 15:41:27 IST
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A very good ques on SHM someone plz solve it........the one who solves it correct will be rated.....Here comes the ques...Just Find the time of the system...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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5 Apr 2008 15:43:44 IST
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Question is vague. Are the pulleys massless? No data given. We need the mass of that block
Anyway its simple. Use constraints and conserve energy to get the answer.
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Will nip in at times to solve problems :)
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5 Apr 2008 15:44:17 IST
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welll all the pulleys are massless and smooth...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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5 Apr 2008 15:44:57 IST
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and mass of the block is M so now is the ques complete???
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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5 Apr 2008 15:46:03 IST
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@ karthik...u r not a JEE consultant r u??well get u r hands dirty and solve the ques...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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Doing calculations on the comp itself... so please excuse my calculation mistakes:
Since it is a conservative system:
1/2mv2+1/2kx2+2kx2 = K
mva + kxv + 4kxv = 0
ma = -5kx
a = -5kx/m
w = sqrt(5k/m)
T = 2pi sqrt(m/5k)
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Will nip in at times to solve problems :)
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5 Apr 2008 15:51:25 IST
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well i think the answer is wrong....mainly b cause in case the block moves up it is influenced only by spring below and not the left spring...note tht the left spring is not connected to the surface...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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5 Apr 2008 15:52:03 IST
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what's the answer
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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5 Apr 2008 15:52:27 IST
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if for the block we consider the eqn...
Mg-kx-T =2Ma
then what we r going to consider the eqn for the spring at left
kx+2T=?
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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5 Apr 2008 15:52:48 IST
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@anand - you didn't get what I was doing. i am conserving the energy of the whole system dude.
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Will nip in at times to solve problems :)
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5 Apr 2008 15:57:14 IST
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@karthik what does 2kx^2 imply in ur first eqn
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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5 Apr 2008 15:57:37 IST
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That comes from constraints....
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5 Apr 2008 16:01:12 IST
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oh yeah i got it ur method s correct but is the answer correct
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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5 Apr 2008 16:27:01 IST
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Let the equilibrium extensions in the spring connected to block be s1 & the other spring be s1/2 = s2 (say) so let the mass be displaced x downwards other spring will get extended by x/2 conserving energy 1/2mv^2 -mgx + 1/2k(s1+x)^2 + 1/2k(s2+x/2)^2 = const mva -mgv + ks1v + kxv + (ks2)v + kx/2 * v = 0 => ma - mg + ks1 + kx + ks2 + kx/2 = 0 now at equilibrium mg -ks1 - ks2 = 0 => mg = ks1 + ks2 so solving both equations ma + 3/2kx = 0 a = - 3kx/2m T = 2piroot(2m/3k)
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5 Apr 2008 16:46:36 IST
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