IIT JEE , AIEEE Forum - Physics , Mechanics

konichiwa2x

Hi,

A block of mass 'm' is connected by a spring is kept opn a horizontal frictionless floor. When the spring is at its natural length 'L' , the block is at a distance 'a' from the wall. Now, the block is moved by a distance of '2a' away from the wall and released. If the collision betweeen the block and the wall is elastic, determine the time period of oscillation?

Answer:

Can u please give me the solution to this problem? thanks for your time.

nitin62225

ans= 4(pi)(m/k)^1/2

3

eqn of shm = (2a)sin (wt)

time period of oscillation = T/2 +2 (pi/(6w))

=4/3 . pi/w

=4(pi)(m/k)^1/2

3

plz rate...

bhupesh

Dear
I would defiantly love to see you solving this problem your self since its a interesting problem .
Here is hint :
You can solve the problem by energy method or force method

the wall has a single Job and thats reversing the direction of velocity of the block and you rest part of the motion is simple harmonic .
did u get my hint from the extreme position to the mean position the time will be decided by the time period of SHM and after that it will move till the wall with SHM and you need to find the time for it to travel that much of distance ( Equations of SHM will help you ) just multiply this by 2 to get the time it need to come back to mean position again .

I believe you can solve the problem yourself now

Let me know for further clarification

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