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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:17:59 IST
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A particle of mass m and charge q is placed in an electric field E which varies with time t as E=E0 sin wt. It will undergo shm of amplitude______???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:20:03 IST
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is it qE0/m???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:22:51 IST
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no dude.......the ans is-
qEo/mw2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:25:09 IST
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wait m solvin
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:32:24 IST
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but how can v get w2 in the ans??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:38:58 IST
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that's wat i m worried abt.....................
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:52:54 IST
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ne1 else plz.....try solvin it.............
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 15:00:35 IST
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Nice and tricky question. Here, we have to get the time-displacement relation of the given SHM, which will give us the required result easily.
Now, E=Eosinwt
Hence, F = qEosinwt
Thus, a(t) = qEosinwt/m
Now, integrating the above, making use of the condition that at t=0, a=0, we have:
|v(t)| = qEocoswt/mw
Again integrating the above, we have:
|x(t)| = qEosinwt/mw2
which is clearly a Simple Harmonic Motion with Amplitude = qEo/mw2
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 15:02:41 IST
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right solution karthik!!!!
i was confused b/w accn a and amplitude a taking same symbols for both.........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 15:07:21 IST
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Yes, you have simply given the formula for the maximum acceleration of the particle, if you have noticed.
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Will nip in at times to solve problems :)
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