IIT JEE , AIEEE Forum - Physics , Mechanics

madmax

A particle is given an init. speed u inside a smooth spherical shell of radius R=1m that it is just able to complete the circle.Acc. of the particle when the particle when velocity is vertical is__________
a)g

10
b)g
c)g

2
d)3g

Its simple.....I got confused at first....Lets see how many of U make the same mistake

feynmann

d) 3g

pavan_2b2

how is 3g

tka

edited

feynmann

at the top most point v^2/1 = g

Now use conservation of energy to find v at height 1 from the ground.

raulrag009

I think it's 3g

ananth_patri

Fenymann plz type in the procedure also/.................

raulrag009

hey feyman wont the acc gravitational due to gravity come into
effect

3g towards the centre and g downwards hence net acc should be

root(9g^2+g^2)=root10 g

ananth_patri

I think the answer is g....ths is bcause the motion executed by the particle is uniform circular motion....thus only acc on the particle when its vel is vertica is g......i think i am right...

srk

answer is c)

2. solution:

the particle is just able to complete the circle therfore its velocity at the bottom is (5gr^)0.5.hence at the point where its velocity is verticle is (gr)^0.5by work-energy principal. centripetal acceleration is v²/r =g. and gravity g, these are paerpendicular to each other, therefore acceleration is (g²+ g²)^0.5=

2g.

^{[ ]}

raulrag009

u are wrong

when v=rootgr the particle's velocity is horizontal not vertical

jatinroxx

The ans is g root10.......

The net acceleration will b the resultant of centripetal acceleration and the acceleration due to gravity........

kavindra

now i have edited this reply.... is it g???

i mean normal reaction counters the centrifugal and only gravity remains...

madmax

Struggle guys struggle!! Lyk I said ,Its simple......CONCEPTS GUYS!!!

computer001

ans is g...its always g only...its jus tht in diff cases the diff components add up 2 give g

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