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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Nov 2007 14:28:55 IST
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A uniform plate of mass M stays horizontally and symmetrically on two wheels rotating in opposite directions.The separrating b/w the wheels is L. the friction coefficient b/w each wheel & plate is . Find the time period of oscillations of the plate if it is slightly displaced along its length and released...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 13:46:55 IST
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yes. I will also like the soln. of this prob.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 13:47:39 IST
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it is a hcv sum.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 14:43:25 IST
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Let the mass be displaced by distance x to the left.
Let the normal forces on the block be N1 and N2.
Since no motion along vertical axis, N1 + N2 = Mg
Also, balance the torque about the center of mass of block (since no rotational motion and torque of gravitational force will be 0) N1(L/2 - x ) = N2(L/2 + x) (N1-N2)L/2= xmg N1-N2=2xMg/L Net force on block = (N1 - N2) =2 xMg/L
Comparing with F=kx, k = 2Mg /L
So, time period = 2 (L/2g )1/2
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