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[Post New]14 Feb 2007 09:50:02 IST
    Subject: spring numerical
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rubina (0)

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A spring of weight W and force constant k is suspended in a horizontal position by two light strings attached to its two ends. Each string makes an angle theta with the vertical . What will be the extension of the spring??
The solution I have has given the force in horizontal position Tsin theta=kx
I want to ask that the Tsin theta acts in left and right directions .So why should not it get cancel?
    
[Post New]14 Feb 2007 09:55:04 IST
    Subject: spring numerical
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kusum (206)

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hi,

firstly ,the forces wont get cancelled as they are not acting at the same point.and secodly tsintheta = kx as u need not take it twice in spring .as kx is on both the sides and kx is balancing Tsintheta and not 2 times of it.
i hope u got ur answer .
cheers!
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[Post New]14 Feb 2007 10:02:18 IST
    Subject: spring numerical
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vish0001 (493)

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yes, kusum is right


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[Post New]14 Feb 2007 10:02:35 IST
    Subject: Re:spring numerical
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rubina (0)

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Hi Pl explain why not 2 times?
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[Post New]14 Feb 2007 10:08:37 IST
    Subject: Re:spring numerical
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rubina (0)

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Though what u r sayin is not fully right but thanks I ve got a gud clue from this.I ve solved it.
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