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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 18:09:56 IST
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A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to (A) x2 (B) ex (C) x (D) logex
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 18:12:07 IST
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is it a)??
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Please watch the BPL match between ManUtd and Arsenal on Sunday at 5:55pm and support only ManUtd...for BPL lovers,update:ManUtd-2 Arsenal-1...
Viva Ronaldoooo
Viva Ronaldoooo
Viva Ronaldoooo
Running down the wing,
Hear United sing,
Viva Ronaldoooo.
-United supporters new chant!!!
Team Plyd Pts
United 32 76
Cls 32 71
Arse 32 70
Who are Liverpool????? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 18:15:53 IST
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 18:19:16 IST
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We can also do it like this a=kx v*dv/dx=kx So,v*dv=kx*dx Integrating, v2/2=kx2/2+c Thus,v2=kx2+c If its given that particle starts at rest,then c=0 and thus,KE=0.5mv2=0.5m(kx2) Thus,a)
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Please watch the BPL match between ManUtd and Arsenal on Sunday at 5:55pm and support only ManUtd...for BPL lovers,update:ManUtd-2 Arsenal-1...
Viva Ronaldoooo
Viva Ronaldoooo
Viva Ronaldoooo
Running down the wing,
Hear United sing,
Viva Ronaldoooo.
-United supporters new chant!!!
Team Plyd Pts
United 32 76
Cls 32 71
Arse 32 70
Who are Liverpool????? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 18:19:27 IST
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a? is it a???
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