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19 Mar 2010 11:24:55 IST

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the coordinates of a particle moving in xy plane is (t^2,2t)at any time t......find the acc and velo

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the coordinates of a particle moving in xy plane is (t^2,2t)at any time t......find the acc and velocity at that time t...

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Nehal Wani

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20 Mar 2010 15:36:59 IST

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Seems to be a parabolic path.

Velocity 2t(in x-direction), 2(in y-direction)

Acceleration 2(in x-direction), 0(in y-direction)

shivanshi asthana

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21 Mar 2010 11:21:57 IST

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how????????method plz...

Nehal Wani

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21 Mar 2010 14:23:00 IST

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was my answer correct

G.Reshma begum

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21 Mar 2010 17:04:01 IST

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x=t^2 y=2t ----------coordinates of particles

(v x --- comp of vel along x -direction)------ dx/dt =2t (acc comp along x direction)-----d^2x/dt^2 =2

(v y ----comp of vel along y -direction)----- dy/dt=2 (acc comp along ydirection0------d^2y/dt^2 =0

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