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Blazing goIITian

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24 Apr 2009 23:14:13 IST

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the radius of gyration of a disc of mass 50 gram and radius 2.5 cm,about an axis passing through its

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the radius of gyration of a disc of mass 50 gram and radius 2.5 cm,about an axis passing through its centre of gravity and perpendicular to the plane is a)0.52 cm b)3.52 cm c)1.76 cm d)6.54 cm (MAHE 2002)

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bella

Hot goIITian

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24 Apr 2009 23:19:20 IST

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ans is C (1.77cm)

BALGANESH

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24 Apr 2009 23:19:28 IST

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1/2mr^2 = mk^2 K = r/root2 = 2.5 / root 2 = 1.76 so the answer is c

surya

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24 Apr 2009 23:37:19 IST

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K^ 2 = I / M for a thin disc passing through centre of mass perpendicular 2 plane of disc I = MR^2/2=> K^2 = R^2/ 2 = > K = R / 2^1/2 => k = 2.5 / 2^ 1/2 = > K = 1.76 cm

Sparkling kid

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25 Apr 2009 11:35:04 IST

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its (c) ......that is 1.76cm....cheers

hot goiitian

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25 Apr 2009 11:39:00 IST

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can it be solved by using any other method?

as the mass is given..

Ankur

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25 Apr 2009 12:01:51 IST

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I think the method which is generally used ( which has been used above ) is the most efficient method of calculating radius of gyration. Answer is coming correct then what's the need to check out for mass

a.boy11

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25 Apr 2009 22:03:50 IST

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Olaaa!! Perrrfect answer.

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