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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: this is from ROTATIONAL MOTION,MOMENT OF INERTIA(2ND ONE)
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rakhiagrawal (31)

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1.IN A BICYCLE RADIUS OF REAR WHEEL IS TWICE THE RADIUS OF FRONT WHEEL.IF Rf &Rr are THE RADIUS OF,Vf &Vr ARE SPEEDS OF TOPMOST POINTS OF WHEEL THEN
(A)Vr=2Vf
(b)Vf=2Vr
(C)Vf=Vr
(d)Vf>Vr
explain how?
    
pannaguma (425)

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let Vcm be velocity of bicycle.
for each wheel draw a triangle, with vertical line passing thre top centre and bottom. now draw lines indicating magnitudes of velocities. Vtop = Vcm*radius for both cases.

thus Vrear = 2 Vfront.


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rakhiagrawal (31)

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sorry my friend.i couldn't create the diagram in my mind according to ur explanation & the ans. given is that both are equal.
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rakhiagrawal (31)

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plz.any 1 give some idea.
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rooney (889)

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EDIT : I gave a shitty answer here

http://14-69-8.blogspot.com
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karthik2007 (3349)

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I am getting option c)

Now, as the cycle as a whole moves with the same speed, the speeds of the centers, ie, the center of mass of the two wheels will be the same, and let it be V.

Consider the rear wheel:

(I hate super and subscripts!! )

Let the speed of the center of mass be V


Let the radius of the rear wheel be R'', and radius of the front wheel be R', and the corresponding notations be used for the velocities of the topmost points.

Now, as the bottommost point is the point of zero velocity (instantaneous)

We have w = V/2R'.

So, v' = 0 + 4R'(V/2R') = 2V.
(As V of bottommost point = 0) - thanks for pointing it out rooney :) )
For the rear wheel :

w = V/R'.

so, v'' (topmost point) = 2R(V/R) = 2V.

So, net speed of the topmost point = 0+2V = 2V

Hence, its clear that both the points move with same velocity of 2Vcom .



Will nip in at times to solve problems :)
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karthik2007 (3349)

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rakhia, you there?

Will nip in at times to solve problems :)
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rooney (889)

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Karthik, you are right.

Answer is C.

But w is not same for both the wheels.

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rakhiagrawal (31)

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yas,w is not same for both.but w & r changes such that v remains constant.but i didn't get how the values of v' & v" came in kartic's ans.
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rooney (889)

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It is calculated by Velocity at point B = Vector sum of ( Velocity at point A + w x Distance of B from A)

http://14-69-8.blogspot.com
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rakhiagrawal (31)

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i m really sorry.but can u plz........... give me the diagram indicating those points in any one case.
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karthik2007 (3349)

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Here it is -


Hope it helps you out.


Will nip in at times to solve problems :)
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rakhiagrawal (31)

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yes,any one.but plz. indicate point A & B as given by rooney so that i can apply the formula given.tankks a lot in advance.
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rakhiagrawal (31)

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finally i understood this & i am satisfied bcoz of u karthik.i don't have words to thank u. thank u verymuch.
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