IIT JEE , AIEEE Forum - Physics , Mechanics

shinee

three particles A B C are situated at the vertices of an equilateral triangle ABC of side d at t=o . each of the particle moves with a constant speed v, A always has its velocity along AB, B along BC , c along CA. at what time will the particles meet each other

i actually didnt get the concept behind this pro. those three people should not meet each other

BALGANESH

the particles would meet at the centre take the component of their vel towards centre i.e vcos30and the distance is d/root3

so we get t =2d/3

akshay.khare91

The particle will meet each other at the circumcenter of triangle ....

so each particle will have to travel a distace d /root 2 ( distance of each particle
at vertex from circumcentre.{can be calculated using geometry} )..

now take component of velocity toward circumcentre . by using that
the angle of equilateral triangle is 60 degrees...

and apply t= s/v to get answer..

computer001

the particles will spiral to the centre

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