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Blazing goIITian

Joined:	16 Mar 2008
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1 Sep 2009 14:10:12 IST

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383

time periiod dammmn!!!!!!!!!!

Kinematics , NewtonsLawsCirMotion , Work Power Energy collisions , Rotation , Gravitation , Simple Harmonic Motion , Fluid Mechanics , Materials Wave Sound , Super Position , units dimensions , com momentum , shm , wave sound

time perido in a pendulum acc upwards is

T=2pie root l/g+a

kkk i am trying to derive this ............ it is easy to derive it from the fraame of the lift u apply a psuedo focrce and its as simple as thaat

now from the frame of the earth...... thatss where the problem starts

can nayone derive me this equation i am getting mad that iam not able to solve it

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Comments (5)

sravanthi

Scorching goIITian

Joined: 4 Apr 2009

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1 Sep 2009 14:52:51 IST

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T (TORQUE) = -m(g+a) l sin( teta) as here T=r x F ( F=m(g+a))

as teta is small T= m(g+a) l teta

I ( MOI) = ML²

q= T/I (FRM T=I q) : so q= -(g+a) teta/ l

q= - w² teta ; w= [(g+a)/l]^0.5

T=2 PI/w

T=2PI [L/(g+a)]^0.5

VARUN RAJ

Blazing goIITian

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1 Sep 2009 18:02:38 IST

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i ma sorry but htis answer is wrong........... if it were rite ........ i would hv thought it before i ma asking u t prove it from the earths frmae nad formt he earths frame u jut cant assume anything dont use any shhortcuts for effective g or whatever otherwise i would hv also done it.......

VARUN RAJ

Blazing goIITian

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1 Sep 2009 18:07:33 IST

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i think as far as i hv worked out this is most probasbly the rite working ............... -mgsin@=x+masin@......... and here x is the acc along the arc........... pls anyone confirm my working

sravanthi

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1 Sep 2009 18:22:49 IST

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@ varun tell me wats the tension in the wire when the simple pendulum is taken upwards, i

think TENSION IS M(g+ a) ,

so here consider the tension in the wire as the force F

VARUN RAJ

Blazing goIITian

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1 Sep 2009 19:49:55 IST

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so the force perpendicuatr to the motion is not (mg+ma) actually these all are shortcuts to solve the main probem................ but i am trying to find how the shortcuts r derived agress t=mg+ma ..... but according to shm....... .... . we hv to take components of force along the direction or tangent to the direction in a pendulum............................. but the value of t is 0 in this so ur argument i fundamentally flawed

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