IIT JEE , AIEEE Forum - Physics , Mechanics

ananth910

A uniform bar of length l and mass m extends horizontally from a wall to the mid point making an angle of 45 degrees with the bar . A block of mass M hangs from the other end of the bar .

If the system is in static equilibrium,determine the tension in the wire and the force exerted on the bar by the wall if m=8kg and M=12kg.The diagram is given:

feynmann

take moment of forces about A . to get the tension . Now use eq condition to find force exerted by wall .

bhupesh

For Static equlibrium Net force must be zero If it is then you can find torque about any point you want It will also be zero . Draw a FBD then use the above conditions to find your answer .

iitian_aakash

question not clearly explained

karthik2007

is the tension 320

2N?

rooney

Along vertical,
N₁ + TSin 45 = 80+120
Along horizontal
TCos45=N₂
Balancing torque abt COM
N₁l/2=120 l/2

Solve to get T=80(2)^1/2 Newtons
N₁=120, N₂=80
So, N =( N₁ ² + N₂ ² )^1/2 =40root(13) Newtons

karthik2007

hmm... i did the same thing... but got 320 root 2 :|

edit - got my error. The answers are as per the above post... they are perfect

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