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sneha.bagri (142)

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A  motor car is going due north at a speed of 50km/h .It makes a 900 left turn without changing the speed .The change in d velocity of d car is abt
a) 50km/h towards west
b) 70km/h towards south-west
c)70km/h towards north-west
d)zero
 
plz tell d correct ans wid explanation.
 
    
rphy (104)

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hi. ok now the change in velocity is v2 - v1
draw the vector diagram. and the resultant should be 70 km/h towards S/W.


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sneha.bagri (142)

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how towards north west?????
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rphy (104)

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oh sorry it is actually along S/W my mistake, jus draw d vector diagram & knock if u need more help.

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sneha.bagri (142)

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y along S/W?
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lakshaydulani (0)

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it shd b 45 degrees right to north
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joyfrancis (1504)

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The ans is (b)
 
Initial velocity in vector form = 5j (j represents the unit vector along the +ve x- axis)
 
Final velocity = 5i or 5(-i) because 90o turn means that it turns due west
 
Hence change in vel = -5i-5j
=70Km/h due south west
 

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amitsingh (273)

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shikharbaid (175)

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The ans is (b)

amit,,, the diagram is correct but shouldnt it be inverted ( left turn )

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tarun_bits (644)

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it turns 90 degree towards left only joyfrancis
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amitsingh (273)

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@shikharbaid.

Look it is not inverted it is the resultant of both the changes

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paridhi_aggarwal (81)

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hi sneha
according to me the answer is [c]
this is because when the car turns left the resultant would then be in the right( west) direction.........i.e the resultant would have components in the west and the north direction

regarding magnitude applying the paralellogram law of vectors
it would be [ (50)^2 +(50)^2+2(50)(50)cos 90]= 70 km/hr

hence 70 km/ hr noth- west

and ya plz rate if correct do let me know the correct ans if wrong

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amitsingh (273)

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Oh i got wat u mean @shikharbaid.
I have edited it
 
Funda is same.
 
 
 

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