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Mechanics

New kid on the Block

 Joined: 29 Jan 2011 Post: 6
16 May 2011 23:44:54 IST
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Two pendulums with natural frequencies f1 and f2 are released in phase at same instant of time. Afte
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Two pendulums with natural frequencies f1 and f2 are released in phase at same instant of time. After what interval will they come in phase again?a) 1/f1 + 1/f2b) 1/f1 - 1/f2c) 1/(f1.f2)d) L.C.M of 1/f1 and 1/f2

Scorching goIITian

Joined: 18 Mar 2010
Posts: 278
17 May 2011 07:25:57 IST
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d)L.C.M of 1/f1 and 1/f2

Blazing goIITian

Joined: 27 Dec 2010
Posts: 1508
17 May 2011 07:59:24 IST
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the answer is (d) that is the lcm of 1/f1 and 1/f2.

New kid on the Block

Joined: 29 Jan 2011
Posts: 6
17 May 2011 15:56:25 IST
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yup, answer is (D).but please give me details....

Scorching goIITian

Joined: 18 Mar 2010
Posts: 278
17 May 2011 17:10:05 IST
4 people liked this

CONSIDER THE FOLLOWING CASE

YOU WILL FIND THE THEY HAVE DIFFERNT I.E IF THE FIRST HAS A TIME PERIOD 1/F  THE THE SECOND ONE HAS A TIME PERIOD 2/F AND CLEARLY FROM THE FIG. WE CAN GET THAT THE TWO ARE IN PHASE INITIALLY AT t=0  and again come in phase at t=2/F (I.E THE LEAST TIME WHEN THEY START FROM ZERO DISPLACEMENT TOGETHER AND THIS CAN BE MATHEMATICALLY  EXPRESSED AS LCM OF THE TWO TIME PERIODS).Hope it's clear now.

New kid on the Block

Joined: 2 Apr 2012
Posts: 1
2 Apr 2012 11:48:45 IST
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Two pendulums with natural frequencies f1 and f2 are released in phase at same instant of time. Afte

Blazing goIITian

Joined: 2 Mar 2012
Posts: 308
2 Apr 2012 12:20:33 IST
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## t =  1/(f1-f2)

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