IIT JEE , AIEEE Forum - Physics , Mechanics - very easy mechanics qns just want confirmation needed

rakesh61

The maximum instantaneous velocity is around the point

B

C

D

A

my friend told ans should be C

but i think it should be B

please confirm whio is correct if possible with reason please answer only if u know Rates are asssured

rakesh61

click on the image to get a clear image

raulrag009

Edited (i interchanged accidently)

It's B

if u draw a tangent at B. it will intersect the xaxis at a much greater angle than B

arpan1

see first thing is that velocity is the slope in displacement - time graph

here slope of B is greater than that of C

hence velocity of B is greater

rate me

arpan1

@ rahulrag

i dont think ur solution is correct

because if u join the topmost point with x- axis u get the largest angle but at this point velocity is zero

ramyani

seems ur frnd is correct.

chemicaltester

no need to find the slopes
also by some c sense u can do that
first of all see the curve
u will observe the bending of curve as irreglar
the point at which the curve is mpre bended with respect to a fixed point say( a) will give the max slope
this hold true only in first quadrant

ashish_banga

hey rakesh u r asking every question from AIPMT today
aakash institute has given it as C
but answer is surely B

raulrag009

edited

rathin_123

is it stright line between b &c. if it then instantteneous velocity remains same during b_c period.so instantteneous velocity is same at b &c.

if not then ans will AT B point

ramyani

draw tangets.

which one is more steep ?

Look the line touching C is steeper.

kundan_leo

i agree with arpan.....
it'll be B

because the answer will be given by dispacemnt - graph.....
and slope of b is greater than that of c.....

rishipratimm

the ans is b....
reason:as stated above

rathin_123

i agree ramyani.but if bc is strigt then... draw tengat they will same

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